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(A). Find the current through each resistor for the circuit in Figure 1.

Use two important figures to express your answers. Your answers should be separated numerically by commas.

(B). Find the potential difference between each resistor and the circuit in the figure.

Two significant figures are sufficient to express your answers. Your answers should be separated numerically by commas.

a) Req= 6ohm

So net current =24/6 =4 A

So

• Current through 2 Ohm = 4A (ans).
• Current through 4 Ohm = 2A (ans).
• Current through 6 Ohm = 4/3A =1.33A (ans)
• Current through 12 Ohm = 2/3A =0.67 An (ans)
• Current through 8 Ohm = 2 A (ans).

b)

• Voltage through 2 Ohm = 4A *2 =8V (ans)
• Voltage through 4 Ohm = 2A*4 =8V (ans)
• Voltage through 6 Ohm = 6*4/3 =8V (ans)
• Voltage through 12 ohm =2/3A*12 =8V (ans)
• Voltage through 8 ohm =2A*8 =16V (ans)

Resistors can be connected in parallel or series to make an electric circuit. Although the current can pass through all resistors in a series combination, the potential difference between them will be different. This is the equivalent resistance to resistors connected in series.

R eq =R 1 +R 2 +R 3 (where; R1,R2, R3....... The resistance of individual resistors

A parallel combination of resistors is when the potential difference across each resistor stays the same but the current flowing through each resistor changes. Find the equivalent resistance for parallel combinations by:

• The Equivalent resistance method is useful for simplifying circuits that have multiple voltage sources or one branch with several series-parallel resistors. It can also be used to create a single voltage source and an equivalent resistance.
• The equivalent resistance is the resistance that can be connected to the voltage source separately, and provides the same source current as in the original circuit.
• The Method of Equivalent Resistance, which is an extension of Ohm's Law and used to calculate the source current in the simplified Circuit, is called the Method of Equivalent Resistance.

Below is the solution to "Find the current through each resistor in the circuit as shown in Figure 1" . Please leave a comment if you have any comments or good solutions. 
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